Question

486:. =6 ( ост.6 )726:. =9 ( ост. 6 )365:. =6 ( ост.5 )​

Answer 1

Ответ:56

Пошаговое объяснение:

Answer 2

It appears you've provided a sequence of divisions and remainders:

1. 486 ÷ ? = 6 (remainder 6)
2. 726 ÷ ? = 9 (remainder 6)
3. 365 ÷ ? = 6 (remainder 5)

To find the missing numbers in these divisions, we can set up equations:

1. Let's call the missing divisor in the first equation "x". So, we have 486 ÷ x = 6.
2. In the second equation, let's call the missing divisor "y". So, we have 726 ÷ y = 9.
3. Finally, in the third equation, let's call the missing divisor "z". So, we have 365 ÷ z = 6.

Now, we can solve for each missing divisor:

1. 486 ÷ x = 6 x = 486 ÷ 6 x = 81

2. 726 ÷ y = 9 y = 726 ÷ 9 y = 81

3. 365 ÷ z = 6 z = 365 ÷ 6 z = 60.83 (rounded to 2 decimal places)

So, the missing divisors are:

1. x = 81
2. y = 81
3. z ≈ 60.83