Question

4 1) 3(x - 2) = 4x;3) 5(y + 3) = 10;5) -4(x - 2) = -6;2) 6(2 - 1) = 18;4) 3(2x - 7) = 9;6) 3(x - 5) = x + 3.​

Answer 1

возможно так

во втором уравнения может быть х стоит?

просто утверждение не получается.

если это не то тогда можете удалить ответ.

Answer 2

Let's solve these equations one by one:

1. 3(x - 2) = 4x

First, distribute the 3 on the left side:

3x - 6 = 4x

Now, subtract 3x from both sides:

-6 = x

So, the solution is x = -6.

2. 6(2 - 1) = 18

Simplify inside the parentheses first:

6(1) = 18

Now, multiply:

6 = 18

This equation is not true, so there is no solution to this equation.

3. 5(y + 3) = 10

First, distribute the 5 on the left side:

5y + 15 = 10

Now, subtract 15 from both sides:

5y = 10 - 15 5y = -5

Now, divide by 5:

y = -5/5 y = -1

So, the solution is y = -1.

4. -4(x - 2) = -6

First, distribute the -4 on the left side:

-4x + 8 = -6

Now, subtract 8 from both sides:

-4x = -6 - 8 -4x = -14

Now, divide by -4:

x = -14 / -4 x = 7/2

So, the solution is x = 7/2.

5. 3(2x - 7) = 9

First, distribute the 3 on the left side:

6x - 21 = 9

Now, add 21 to both sides:

6x = 9 + 21 6x = 30

Now, divide by 6:

x = 30 / 6 x = 5

So, the solution is x = 5.

6. 3(x - 5) = x + 3

First, distribute the 3 on the left side:

3x - 15 = x + 3

Now, subtract x from both sides:

2x - 15 = 3

Now, add 15 to both sides:

2x = 3 + 15 2x = 18

Now, divide by 2:

x = 18 / 2 x = 9

So, the solution is x = 9.