Question

9/14-3/7+15/28 ;1/6+1/4+1/8 ;13/18-29/45+8/15;​

Answer 1

Ответ:

9/14-3/7+15/28=18/28-12/27+15/28=21/28

1/6+1/4+1/8=4+6+3/24=13/24

13/18-29/45+8/15=65-58+48/90=55/90

Answer 2

Let's solve each of these arithmetic expressions step by step:

1. $\frac{9}{14} - \frac{3}{7} + \frac{15}{28}$

   To perform these calculations, we need a common denominator. The least common multiple of 14, 7, and 28 is 28. So, we'll rewrite the fractions with a common denominator:

   $\frac{9}{14} = \frac{9 \cdot 2}{14 \cdot 2} = \frac{18}{28}$

   $\frac{3}{7} = \frac{3 \cdot 4}{7 \cdot 4} = \frac{12}{28}$

   Now, we can add and subtract the fractions:

   $\frac{18}{28} - \frac{12}{28} + \frac{15}{28} = \frac{18 - 12 + 15}{28} = \frac{21}{28}$

2. $\frac{1}{6} + \frac{1}{4} + \frac{1}{8}$

   To add these fractions, we also need a common denominator. The least common multiple of 6, 4, and 8 is 24. So, we'll rewrite the fractions with a common denominator:

   $\frac{1}{6} = \frac{1 \cdot 4}{6 \cdot 4} = \frac{4}{24}$

   $\frac{1}{4} = \frac{1 \cdot 6}{4 \cdot 6} = \frac{6}{24}$

   $\frac{1}{8} = \frac{1 \cdot 3}{8 \cdot 3} = \frac{3}{24}$

   Now, we can add the fractions:

   $\frac{4}{24} + \frac{6}{24} + \frac{3}{24} = \frac{4 + 6 + 3}{24} = \frac{13}{24}$

3. $\frac{13}{18} - \frac{29}{45} + \frac{8}{15}$

   For this expression, we again need a common denominator. The least common multiple of 18, 45, and 15 is 90. So, we'll rewrite the fractions with a common denominator:

   $\frac{13}{18} = \frac{13 \cdot 5}{18 \cdot 5} = \frac{65}{90}$

   $\frac{29}{45} = \frac{29 \cdot 2}{45 \cdot 2} = \frac{58}{90}$

   $\frac{8}{15} = \frac{8 \cdot 6}{15 \cdot 6} = \frac{48}{90}$

   Now, we can add and subtract the fractions:

   $\frac{65}{90} - \frac{58}{90} + \frac{48}{90} = \frac{65 - 58 + 48}{90} = \frac{55}{90}$