Question

987)1) |x|= < 7;2) |x| < -8;3) |x| < 0;4) |x) < 6,5;​

Answer 1

Ответ:

X ∈(-7, 7)

X ∈ (-бесконечности;-8)

X ∈(-бесконечности; 0)

X ∈(-6,5, 6,5)

Пошаговое объяснение:

Answer 2

Let's analyze each of the inequalities you've provided:

1. |x| ≤ 7: This inequality means that the absolute value of x is less than or equal to 7. In mathematical notation, it can be expressed as: -7 ≤ x ≤ 7

2. |x| < -8: This inequality states that the absolute value of x is less than -8. However, the absolute value of any real number is always non-negative (greater than or equal to 0), so this inequality is not possible for any real number x. In other words, there are no real values of x that satisfy this inequality.

3. |x| < 0: This inequality states that the absolute value of x is less than 0. The absolute value of any real number is always non-negative, so there are no real values of x that satisfy this inequality.

4. |x| < 6,5: This inequality seems to be written in an unusual format with a comma. If you meant to write it as two separate inequalities, it would look like this: |x| < 6 and |x| < 5

For the first part, |x| < 6, this means that the absolute value of x is less than 6: -6 < x < 6

For the second part, |x| < 5, this means that the absolute value of x is less than 5: -5 < x < 5

So, combining both inequalities: -6 < x < 6 and -5 < x < 5

The values of x that satisfy both conditions are between -5 and 5 (exclusive), which can be expressed as: -5 < x < 5

If you have any further questions or if you meant something different with the inequalities, please clarify.