Question

103/580+102/580-(152/580-68/580) =?/? 619/925-586/925+53/925=?/?

Answer 1

Ответ:

$\frac{103}{580} + \frac{102}{580} - ( \frac{152}{580} - \frac{68}{580} ) = \frac{121}{580} \\ \\ \frac{205}{580} - ( \frac{84}{580} ) = \\ \\ \frac{121}{580} \\ \\ \\ \frac{619}{925} - \frac{586}{925} + \frac{53}{925} = \\ \\ \frac{86}{925}$

ответ 1: 121/580

ответ 2: 86/925

Answer 2

Ответ:

нажмите на фото там все примеры

Answer 3

To solve the expression, let's break it down step by step:

1. $\frac{103}{580} + \frac{102}{580} - \left( \frac{152}{580} - \frac{68}{580} \right)$

First, simplify the fractions inside the parentheses:

$\frac{152}{580} - \frac{68}{580} = \frac{84}{580}$

Next, substitute this back into the original expression:

$\frac{103}{580} + \frac{102}{580} - \frac{84}{580}$

Combine the numerators:

$\frac{205}{580} - \frac{84}{580}$

Subtract the fractions:

$\frac{121}{580}$

2. $\frac{619}{925} - \frac{586}{925} + \frac{53}{925}$

Subtract the fractions:

$\frac{33}{925} + \frac{53}{925}$

Combine the numerators:

$\frac{86}{925}$

Now, the two fractions are:

$\frac{121}{580}$ and $\frac{86}{925}$.

If you want to express them as a ratio, it would be:

$\frac{121}{580} : \frac{86}{925}$.