Question

А) m = m + 4;б) k = 2k ;В) 8x = 4х + 16;г) | x+5| - 3 = - 16.​

Answer 1

Ответ:

ниже

Пошаговое объяснение:

а) m-m=4

0=4

решений нет

б) k=2k

k=0

в) 8x-4x=16

4x=16

x=4

г)  | x+5| = -16+3

| x+5|= - 13

Решений нет (тк отрицательное число не может быть)

Answer 2

Let's analyze each equation:

А) $m = m + 4$: This equation is contradictory. If you subtract $m$ from both sides, you get $0 = 4$, which is not true. Therefore, there is no solution for $m$ that satisfies this equation.

Б) $k = 2k$: If you subtract $k$ from both sides, you get $0 = k$. This equation is true only if $k = 0$. So, the solution is $k = 0$.

В) $8x = 4x + 16$: Subtract $4x$ from both sides to solve for $x$: $8x - 4x = 16$ $4x = 16$ $x = 4$ So, the solution is $x = 4$.

Г) $| x+5| - 3 = -16$: Add 3 to both sides: $| x+5| = -13$ The absolute value of any real number is non-negative, so there is no solution for $x$ that satisfies this equation. Therefore, the solution is an empty set.

In summary:

• Equation А has no solution.
• Equation Б has a solution $k = 0$.
• Equation В has a solution $x = 4$.
• Equation Г has no solution.