Question

4) 3,4 + 2 y = 7(y-2,3); 5) 0,2(7 - 2y)= 2,3 -0,3(y-6); ;

Answer 1

Ответ:

3,9

-27

Пошаговое объяснение:

4)3,4+2у=7(у-2,3)

3,4+2у=7у-16,1

-5у=-19,5

у=3,9

5)0,2(7-2у)=2,3-0,3(у-6)

1,4-0,4у=2,3-0,3у+1,8

-0,1у=2,7

у=-27

Answer 2

Let's solve each of the equations step by step:

Equation 4: $3.4 + 2y = 7(y - 2.3)$

Step 1: Distribute on the right side:

$3.4 + 2y = 7y - 16.1$

Step 2: Combine like terms:

$2y - 7y = -16.1 - 3.4$

$-5y = -19.5$

Step 3: Solve for $y$:

$y = \frac{-19.5}{-5}$

$y = 3.9$

Equation 5: $0.2(7 - 2y) = 2.3 - 0.3(y - 6)$

Step 1: Distribute on both sides:

$1.4 - 0.4y = 2.3 - 0.3y + 1.8$

Step 2: Combine like terms:

$-0.4y + 0.3y = 2.3 - 1.8 - 1.4$

$-0.1y = -1.9$

Step 3: Solve for $y$:

$y = \frac{-1.9}{-0.1}$

$y = 19$

So, the solutions are $y = 3.9$ for Equation 4 and $y = 19$ for Equation 5.