
4y+3(y-3)=40 5(2a+10)=5a+100 5y+2(y-4)=42-3y 7+5(x+1)=x+16 6(x+2)-10=4x+28 8z-5=3(z+19)-7
5x+4(x+1)=23+8x 6y-3(y+4)=23-2y 4x-10=2(4-x)

Ответы на вопрос

Ответ:
1) 7
2)10
3)540
4)1
5)13
6)11
7)19
8)7
9)3



Відповідь:у=7
Покрокове пояснення:



Let's solve each of these equations step by step:
4y + 3(y - 3) = 40 Distribute the 3 on the left side: 4y + 3y - 9 = 40 Combine like terms: 7y - 9 = 40 Add 9 to both sides: 7y = 49 Divide by 7: y = 7
5(2a + 10) = 5a + 100 Distribute the 5 on the left side: 10a + 50 = 5a + 100 Move all the terms with 'a' to one side and the constants to the other: 10a - 5a = 100 - 50 Simplify: 5a = 50 Divide by 5: a = 10
5y + 2(y - 4) = 42 - 3y Distribute the 2 on the left side: 5y + 2y - 8 = 42 - 3y Combine like terms: 7y - 8 = 42 - 3y Add 3y to both sides: 10y - 8 = 42 Add 8 to both sides: 10y = 50 Divide by 10: y = 5
7 + 5(x + 1) = x + 16 Distribute the 5 on the left side: 7 + 5x + 5 = x + 16 Combine like terms: 5x + 12 = x + 16 Subtract x from both sides: 4x + 12 = 16 Subtract 12 from both sides: 4x = 4 Divide by 4: x = 1
6(x + 2) - 10 = 4x + 28 Distribute the 6 on the left side: 6x + 12 - 10 = 4x + 28 Combine like terms: 6x + 2 = 4x + 28 Subtract 4x from both sides: 2x + 2 = 28 Subtract 2 from both sides: 2x = 26 Divide by 2: x = 13
8z - 5 = 3(z + 19) - 7 Distribute the 3 on the right side: 8z - 5 = 3z + 57 - 7 Combine like terms: 8z - 5 = 3z + 50 Subtract 3z from both sides: 5z - 5 = 50 Add 5 to both sides: 5z = 55 Divide by 5: z = 11
5x + 4(x + 1) = 23 + 8x Distribute the 4 on the left side: 5x + 4x + 4 = 23 + 8x Combine like terms: 9x + 4 = 23 + 8x Subtract 8x from both sides: x + 4 = 23 Subtract 4 from both sides: x = 19
6y - 3(y + 4) = 23 - 2y Distribute the -3 on the left side: 6y - 3y - 12 = 23 - 2y Combine like terms: 3y - 12 = 23 - 2y Add 2y to both sides: 5y - 12 = 23 Add 12 to both sides: 5y = 35 Divide by 5: y = 7
4x - 10 = 2(4 - x) Distribute the 2 on the right side: 4x - 10 = 8 - 2x Add 2x to both sides: 6x - 10 = 8 Add 10 to both sides: 6x = 18 Divide by 6: x = 3
I hope this helps!


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