Question

(7/48:5/240):6 3/10∙4 1/5 СРОЧНОООО пжжж

Answer 1

ответ: 14/3

(7/48 × 240/5) : 63/10 × 21/5

(7/48 × 48) × 10/63 × 21/5

7 × 2/63 × 21

2/9 × 21

2/3 × 7 = 14/3

Answer 2

To solve the given expression (7/48:5/240):6 + 3/10∙4 + 1/5, we need to follow the order of operations (PEMDAS/BODMAS).

Step 1: Simplify the division

First, let's simplify the division (7/48:5/240). To divide fractions, we multiply the first fraction by the reciprocal of the second fraction.

The reciprocal of 5/240 is 240/5, so the division can be rewritten as (7/48) * (240/5).

Step 2: Multiply the fractions

Next, we multiply the fractions (7/48) * (240/5). To multiply fractions, we multiply the numerators together and the denominators together.

(7/48) * (240/5) = (7 * 240) / (48 * 5) = 1680 / 240

Step 3: Simplify the fraction

To simplify the fraction 1680/240, we can divide both the numerator and denominator by their greatest common divisor (GCD). The GCD of 1680 and 240 is 240.

1680 / 240 = 7

Step 4: Simplify the remaining expression

Now that we have simplified the division, we can continue simplifying the remaining expression: 7 + 3/10∙4 + 1/5.

Step 5: Multiply and add

Next, we multiply 3/10 by 4: (3/10) * 4 = 12/10 = 6/5.

Step 6: Add the fractions

Finally, we add the fractions together: 7 + 6/5 + 1/5.

To add fractions, we need a common denominator. The common denominator for 6/5 and 1/5 is 5.

7 + 6/5 + 1/5 = 7 + (6 + 1)/5 = 7 + 7/5

Step 7: Convert to a mixed number (if necessary)

If we want to express the result as a mixed number, we can divide 7 by 5 and express the remainder as a fraction.

7 + 7/5 = 1 2/5

Therefore, the solution to the expression (7/48:5/240):6 + 3/10∙4 + 1/5 is 1 2/5.

Please note that the given expression was solved using the order of operations and the rules for arithmetic operations with fractions.