Question

Помогите пожалуйста! Снегоуборочная машина убрала 17 целых 1/7 т снега за 3 целых 3/4 часа. Сколько снега он уберет за 7 часов, если будет работать с той же производительностью?

Answer 1

Пропорция
17 1/7 x
——– = ——
3 3/4 7

3 3/4x = 17 1/7 * 7
3 3/4x = 120
x=120:3 3/4
(переводим в десятичную целую часть умножаем на знаменатель и прибавляем числитель , получается 15/4 = 3,75)
х=120:3,75
х=32

32 тонны

Answer 2

To solve this problem, we can use the concept of unit rates.

First, let's find the unit rate of snow cleared per hour. We know that the snowplow cleared 17 1/7 tons of snow in 3 3/4 hours. To find the unit rate, we divide the amount of snow cleared by the time taken:

17 1/7 tons / 3 3/4 hours

To simplify the calculation, let's convert the mixed numbers to improper fractions:

(120/7) tons / (15/4) hours

To divide fractions, we multiply the first fraction by the reciprocal of the second fraction:

(120/7) tons * (4/15) hours

Now, let's multiply the numerators and denominators:

(120 * 4) / (7 * 15) = 480 / 105

Simplifying the fraction, we get:

16/3 tons per hour

So, the snowplow clears 16/3 tons of snow per hour.

Now, we can find how much snow the snowplow will clear in 7 hours by multiplying the unit rate by the number of hours:

(16/3 tons/hour) * 7 hours = (16/3) * 7 = 112/3 tons

Simplifying the fraction, we get:

37 1/3 tons

Therefore, if the snowplow continues to work at the same rate, it will clear 37 1/3 tons of snow in 7 hours.

Please let me know if you need any further assistance!