
На межпланетной космической санкции хранились контейнеры с топливом весом 13,15,16,17,18 и 21
тонна. Первый космический корабль забрал два контейнера, второй космический корабль забрал 3 контейнера. При этом вес топлива, которые забрал второй корабль в 2 раза больше веса топлива, который забрал первый корабль. Найдите вес контейнера, который остался на станции(в тонна).

Ответы на вопрос

Ответ:
16
Пошаговое объяснение:
1) 13+15=28
2) 18+17+21=56, что в 2 раза больше первого



Calculation of the Remaining Fuel Container Weight
To find the weight of the fuel container that remained on the station, we need to analyze the information provided.
According to the question, there were containers with fuel weights of 13, 15, 16, 17, 18, and 21 tons. The first spaceship took two containers, and the second spaceship took three containers. Additionally, the weight of the fuel taken by the second spaceship is twice the weight taken by the first spaceship.
Let's assign variables to the weights of the containers: - Let x represent the weight of the container taken by the first spaceship. - Then, 2x represents the weight of the containers taken by the second spaceship.
To find the weight of the container that remained on the station, we need to subtract the total weight of the containers taken by both spaceships from the total weight of all the containers.
The total weight of all the containers is: 13 + 15 + 16 + 17 + 18 + 21 = 100 tons.
The total weight of the containers taken by both spaceships is: 2x + 3(2x) = 2x + 6x = 8x.
Therefore, the weight of the container that remained on the station is: 100 - 8x.
Now, we know that the weight of the container taken by the second spaceship is twice the weight taken by the first spaceship. So, we can set up the equation:
2x = 2(13 + 15 + 16 + 17 + 18 + 21) - 8x.
Simplifying the equation, we get: 2x = 2(100) - 8x, 2x = 200 - 8x, 10x = 200, x = 20.
Therefore, the weight of the container taken by the first spaceship is 20 tons.
To find the weight of the container that remained on the station, we substitute the value of x into the equation: 100 - 8x = 100 - 8(20) = 100 - 160 = -60.
However, a negative weight does not make sense in this context. It seems there might be an error in the given information or calculation. Please double-check the weights of the containers and the conditions of the problem to ensure accuracy.


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