Question

Помогите пожалуйста срочно надо найдите сумму всех натуральных чисел меньше 334 и кратных 3​

Answer 1

Ответ

Всего таких чисел 111 (334:3)

Чтобы найти их суму можно  использовать формуу сумы арифметической прогрессии.

первый член прогресии - 3. Разность прогрессии=3 Последний член прогрессии = 333

S=$\frac{a1+a111}{2} *111=\frac{3+333}{2} *111=18648$

Answer 2

Calculating the Sum of Natural Numbers Less Than 334 and Divisible by 3

To find the sum of all natural numbers less than 334 and divisible by 3, we can use the formula for the sum of an arithmetic series. The formula for the sum of the first n terms of an arithmetic series is given by:

Sum = n/2 * (first term + last term)

In this case, we need to find the sum of all natural numbers less than 334 and divisible by 3. We can find the last term using the formula:

last term = (last multiple of 3 less than 334)

The last multiple of 3 less than 334 is 333. Now, we can calculate the number of terms in the series using the formula:

number of terms = (last term - first term)/common difference + 1

In this case, the first term is 3, the last term is 333, and the common difference is 3. Plugging these values into the formula, we get:

number of terms = (333 - 3)/3 + 1 = 111

Now, we can calculate the sum using the formula for the sum of an arithmetic series:

Sum = 111/2 * (3 + 333) = 111/2 * 336 = 18648

So, the sum of all natural numbers less than 334 and divisible by 3 is 18648.