Question

2. Две машины выехали одновременно из пункта А в пункт В, Первая машина ехала со скоростью 70 км/ч, а вторая со скоростью на 35 км/ч больше, чем первая, Поэтому первая машина в пункт В добралась на 1ч позже, чем вторая машина. Сколько времени понадобилось второй машине чтобы прибыть в пункт В?​

Answer 1

Ответ:

Пошаговое объяснение:

Скорость второй машины:

70+35=105 км/час

Время в пути второй машины t часов.

Время в пути первой машины ( t+1) час.

Путь  равный.

S=V*t

70(t+1)=105t

70t+70=105t

105t-70t=70

35t=70

t=70/35

t=2 часа -время в пути второй машины.

Answer 2

Problem Analysis

We are given that two cars start simultaneously from point A and travel to point B. The first car travels at a speed of 70 km/h, while the second car travels at a speed that is 35 km/h faster than the first car. The first car arrives at point B 1 hour later than the second car. We need to determine how much time it took for the second car to arrive at point B.

Solution

Let's assume that the time taken by the second car to reach point B is t hours. Since the first car arrived 1 hour later than the second car, the time taken by the first car to reach point B is t + 1 hours.

We can use the formula distance = speed × time to calculate the distance traveled by each car. The distance traveled by the first car is 70 × (t + 1) km, and the distance traveled by the second car is (70 + 35) × t km.

Since both cars traveled the same distance from point A to point B, we can set up the following equation:

70 × (t + 1) = (70 + 35) × t

Now, let's solve this equation to find the value of t.

70t + 70 = 70t + 35t

Simplifying the equation:

70 = 35t

Dividing both sides of the equation by 35:

t = 2

Therefore, it took the second car 2 hours to arrive at point B.

Answer

The second car took 2 hours to arrive at point B.