Question

Какое расстояние в километрах пройдёт катер за 5 часов, двигаясь против течения реки, если известно, что скорость течения реки 1200 м/ч и это составляет 0,1 собственной скорости катера?

Answer 1

Ответ: 54 км

Пошаговое объяснение:

0,1 = 1/10

1)1200:1•10=12000(м/ч) - 12 км/ч - собственная скорость

2) 12000-1200=10800(м/ч) - скорость против течения

3) 10800•5=54000м = 54 км - расстояние за 5 часов

Answer 2

Calculation of Distance Traveled by the Boat

To calculate the distance traveled by the boat in 5 hours while moving against the current of the river, we need to consider the boat's speed and the speed of the river current.

Given: - Boat's speed: unknown - River current speed: 1200 m/h - River current speed as a fraction of the boat's speed: 0.1

Let's denote the boat's speed as B.

The effective speed of the boat against the current can be calculated using the formula:

Effective speed = Boat's speed - River current speed

Since the river current speed is given as a fraction of the boat's speed, we can write:

Effective speed = B - 0.1B

Simplifying the equation, we get:

Effective speed = 0.9B

Now, we can calculate the distance traveled by the boat using the formula:

Distance = Speed × Time

Substituting the effective speed into the formula, we get:

Distance = (0.9B) × 5

Simplifying further, we have:

Distance = 4.5B

Therefore, the distance traveled by the boat in 5 hours, moving against the current of the river, is 4.5 times the boat's speed.

Please note that the boat's speed is not provided in the question, so we cannot calculate the exact distance without that information.