Question

6 класс 3(х-4) +2(х-6) =12 10(х-2) -5(х+3) =15 6(х-2) -3(х+5) =21

Answer 1

Ответ:

Пошаговое объяснение:

3(х-4) +2(х-6) =12

3х-12+2х-12=12

3х+2х=12+12+12

5х=36

х=36:5

х=7.2

Проверка:

3(7.2-4) +2(7.2-6) =12

10(х-2) -5(х+3) =15

10х-20-5х-15=15

10х-5х=15+20+15

5х=50

х=50:5

х=10

Проверка:

10(10-2) -5(10+3) =15

6(х-2) -3(х+5) =21

6х-12-3х-15=21

6х-3х=21+12+15

3х=48

х=48:3

х=16

Проверка:

6(16-2) -3(16+5) =21

Answer 2

Ответ:

1) 3(х-4) +2(х-6) =12

3х -12 +2х-12=12

3х+2х -12-12 =12

5х -24 =12

5х = 12+24

5х=36

х=7,2

2) 10х-20-5х-15=15

10х -5х-20-15=15

5х-35=15

5х = 15+35

5х = 50

х=10

3) 6х -12-3х-15=21

6х-3х-12-15=21

3х-27=21

3х=21+27

3х=48

х=16

Answer 3

I can help you with your math problem. Here is the detailed solution:

First, we need to simplify the equations by distributing the coefficients and combining the like terms. We get:

$$9x - 24 + 4x - 12 = 12 + 10x - 20 - 5x - 15$$ $$6x - 12 - 3x - 15 = 15 + 6x - 12 - 3x - 15$$

Then, we can subtract the same terms from both sides of the equations. We get:

$$8x - 36 = 10x - 23$$ $$0 = 0$$

Next, we can isolate x by subtracting 8x from both sides of the first equation and dividing by 2. We get:

$$-36 = 2x - 23$$ $$x = \frac{13}{2}$$

The second equation is always true, so it does not give us any information about x. Therefore, the solution is x = 13/2.Ответь+подробно.++6+класс++3(х-4)++2(х-6)+=12+10(х-2)+-5(х+3)+=15+6(х-2)+-3(х+5)+=21+