Question

10\х-1 - 14\x = 3 решите,плиз

Answer 1

ОДЗ: x≠0; 1
10x/(x-1)*x - 14(x-1)/(x-1)*x= 3*(x-1)x/(x-1)x
10x-14x+14=3x²-3x
3x²-3x-10x+14x-14=0
3x²+x-14=0
D=1+168=169
x1= (-1+13)/6= 2
x2= (-1-13)/6= -7/3

Answer 2

ОДЗ: x≠0; 1
10x/(x-1)*x - 14(x-1)/(x-1)*x= 3*(x-1)x/(x-1)x
10x-14x+14=3x²-3x
3x²-3x-10x+14x-14=0
3x²+x-14=0
D=1+168=169
x1= (-1+13)/6= 2
x2= (-1-13)/6= -7/3 2141

Answer 3

To solve the equation 10x-1 - 14/x = 3, we can follow these steps:

1. Multiply both sides by x to get rid of the denominator:

   10x^2 - 14 = 3x

2. Move all the terms to one side of the equation:

   10x^2 - 3x - 14 = 0

3. Use the quadratic formula to solve for x:

   x = (-b ± sqrt(b^2 - 4ac)) / 2a

   where a = 10, b = -3, and c = -14.

   Plugging in these values, we get:

   x = (3 ± sqrt(3^2 - 4(10)(-14))) / 2(10) = (3 ± sqrt(649)) / 20

   Therefore, the solutions are:

   x = (3 + sqrt(649)) / 20 ≈ 1.403 x = (3 - sqrt(649)) / 20 ≈ -0.883

So the solutions to the equation are approximately x = 1.403 and x = -0.883.