
Из точки А ,удаленной от прямой b на расстояние 7 см,проведены к ней перпендикуляр АВ и наклонная
АС( В и С принадлежат прямой b) Найдите ВС,если угол САВ= 45°.

Ответы на вопрос




Problem Analysis
We are given a point A that is located at a distance of 7 cm from a line b. From point A, a perpendicular AB is drawn to line b, and a line AC is drawn at an angle of 45 degrees with line AB. We need to find the length of line segment BC.Solution
To find the length of line segment BC, we can use trigonometry and the given information.Let's denote the length of line segment BC as x.
Since angle SAB = 45 degrees, we can use the trigonometric relationship between the sides of a right triangle to find the length of AB.
Using the sine function, we have:
sin(SAB) = AB / AS
Since angle SAB = 45 degrees and AS = 7 cm, we can substitute these values into the equation:
sin(45) = AB / 7
Simplifying, we find:
AB = 7 * sin(45)
Now, we can use the cosine function to find the length of BC.
Using the cosine function, we have:
cos(SAB) = BC / AB
Since angle SAB = 45 degrees and AB is the length we just calculated, we can substitute these values into the equation:
cos(45) = x / (7 * sin(45))
Simplifying, we find:
x = (7 * sin(45)) * cos(45)
Now, we can calculate the value of x using the given information.
Calculation
Let's calculate the value of x using the given information.Using a calculator, we find:
sin(45) = 0.7071 cos(45) = 0.7071
Substituting these values into the equation, we have:
x = (7 * 0.7071) * 0.7071
Simplifying, we find:
x ≈ 3.5355 cm
Therefore, the length of line segment BC is approximately 3.5355 cm.
Answer
The length of line segment BC is approximately 3.5355 cm.

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