Question

Точка О - центр окружности , на которой лежат точки А,В и С . Известно, что <АВС= 56 и <ОАВ= 15. Найдите угол ВСО. Ответ дайте в градусах.

Answer 1

Проведем радиус BO; треуг. AOB - равнобед. (AO=BO=радиусы), значит, угол OBA= углу OAB=15. Угол OBC=56-15=41. Треуг. COB - равнобедренный (BO=CO=радиусы), значит, угол BCO = углу ОВС = 41
Ответ:41

Answer 2

Problem Analysis

We are given that point O is the center of a circle on which points A, B, and C lie. We also know that angle ABS is 56 degrees and angle OAB is 15 degrees. We need to find angle BCO.

Solution

To find angle BCO, we can use the fact that the angle at the center of a circle is twice the angle at the circumference that subtends the same arc. In this case, angle BCO subtends the same arc as angle BAS.

Let's denote angle BCO as x. Since angle ABS is 56 degrees, angle BAS is also 56 degrees. Therefore, angle BCO is twice angle BAS, which means angle BCO is 2 * 56 = 112 degrees.

So, the angle BCO is 112 degrees.

Answer

The angle BCO is 112 degrees.