Question

2.Знайдіть сторони рівнобедреного трикутника, якщо його периметр дорівнює 100 см, а бічна сторона на 11 см більша за основу.​

Answer 1

Ответ:

АВ=ВС=37см, АС=26 см

Объяснение:

Обозначим данный треугольник, как ∆АВС

Дано:

∆АВС

АВ=ВС

Р=100см

АВ-АС=11см

Найти: АВ,ВС,АС-?

Решение.

Пусть АВ=ВС=х см. Тогда АС=х-11 см.

Всего: x+x+x-11 или 100см

Составим и решим уравнение

х+х+х-11=100

3х=100+11

3х=111|÷3

х=37

Значит, АВ=ВС=37см.

2)АС=37-11=26см

Answer 2

Finding the Sides of an Isosceles Triangle

To find the sides of an isosceles triangle, we need to consider the given information. In this case, we are given that the perimeter of the triangle is 100 cm, and the side length is 11 cm greater than the base.

Let's assume that the base of the triangle is represented by the variable 'x'. Since the side length is 11 cm greater than the base, the other two sides can be represented as 'x + 11' cm.

The perimeter of a triangle is the sum of all its sides. In this case, the perimeter is given as 100 cm. So we can set up the following equation:

x + x + 11 + x + 11 = 100

Simplifying the equation, we get:

3x + 22 = 100

Subtracting 22 from both sides:

3x = 78

Dividing both sides by 3:

x = 26

Therefore, the base of the triangle is 26 cm, and the other two sides are 26 + 11 = 37 cm.

So, the sides of the isosceles triangle are 26 cm, 37 cm, and 37 cm.