Question

Знайдіть сторони паралелограма, периметр якого дорівнює 60 см, а одна з сторін на 4 см більш за другу.

Answer 1

Ответ:

Противоположные стороны параллелограмма равны между собой

Одна сторона Х

Вторая Х+4

(Х+Х+4)•2=60

4Х+8=60

4Х=60-8

4Х=52

Х=52:4

Х=13

Одна сторона 13 см

Вторая 13+4=17 см

Ответ 13 см;13 см;17 см;17 см;

Объяснение:

Answer 2

В параллелограмме противоположные стороны равны.

Значит нам даны ширина и длина

Периметр параллелограмма равен удвоенной сумме ширины и длины.

составим и решим уравнение

пусть х см - большая из сторон, тогда (х-4) см - меньшая

60=2(х+(х-4))

2*(х+х-4)=60

2х-4=60:2

2х-4=30

2х=30+4

2х=34

х=34:2

х=17 (см)- большая сторона

17-4=13(см) - меньшая сторона

Answer 3

Finding the Sides of a Parallelogram

To find the sides of a parallelogram, we need to consider the given information. In this case, we are given that the perimeter of the parallelogram is 60 cm, and one of the sides is 4 cm longer than the other side.

Let's assume that one of the sides of the parallelogram is x cm. Since the other side is 4 cm longer, the length of the other side can be represented as x + 4 cm.

Calculating the Perimeter

The perimeter of a parallelogram is the sum of all its sides. In this case, we have two sides, each with a length of x cm and x + 4 cm, respectively.

The perimeter is given as 60 cm. Therefore, we can set up the following equation:

2x + 2(x + 4) = 60

Simplifying the equation, we get:

2x + 2x + 8 = 60

Combining like terms, we have:

4x + 8 = 60

Subtracting 8 from both sides, we get:

4x = 52

Dividing both sides by 4, we find:

x = 13

Finding the Length of the Other Side

Now that we have found the value of x, we can substitute it back into the equation to find the length of the other side.

The length of the other side is x + 4 cm, which becomes 13 + 4 = 17 cm.

Therefore, the sides of the parallelogram are 13 cm and 17 cm.

Conclusion

The sides of the parallelogram, with one side being 4 cm longer than the other, are 13 cm and 17 cm, respectively.