Question

у рівнобедрений трикутник вписано коло що ділить сторону у відношенні 2 3 починаючи від основи знайдіть периметр якщо його основа дорівнює 12 см

Answer 1

Ответ:

28

Объяснение:

Нехай основа =12=3x

Бічна=12:3*2=8

P=12+8*2

Answer 2

Finding the Perimeter of an Isosceles Triangle Inscribed in a Circle

To find the perimeter of an isosceles triangle inscribed in a circle, we need to determine the lengths of the triangle's sides. In this case, we are given that one side of the triangle, the base, is 12 cm long. We also know that the other two sides are divided in a 2:3 ratio, starting from the base.

Let's denote the length of the base as b and the lengths of the other two sides as a and c. According to the given information, we have:

a = 2/5 * b (since it is divided in a 2:3 ratio, and the base is divided into 5 parts) c = 3/5 * b (since it is divided in a 2:3 ratio, and the base is divided into 5 parts)

To find the perimeter of the triangle, we need to add up the lengths of all three sides:

Perimeter = a + b + c

Substituting the values of a and c in terms of b, we get:

Perimeter = (2/5 * b) + b + (3/5 * b)

Simplifying the expression, we have:

Perimeter = (2/5 + 1 + 3/5) * b

Perimeter = (10/5) * b

Perimeter = 2 * b

Since we are given that the base (b) is 12 cm, we can substitute this value into the equation to find the perimeter:

Perimeter = 2 * 12

Perimeter = 24 cm

Therefore, the perimeter of the isosceles triangle inscribed in the circle is 24 cm.