Question

CE=4;DE=5 CD-? C=90º

Answer 1

CD=√(5*5 - 4*4)=3 за теоремою Піфагора

Answer 2

Так как этот треугольник прямоугольный , то теореме Пифагора DE^2=CE^2+CD^2
25=16+х^2
Х^2=9
Х=9

Answer 3

To find the value of CD, we can use the Law of Cosines, which states that in any triangle:

c^2 = a^2 + b^2 - 2ab * cos(C)

where:

• c is the side opposite angle C,
• a and b are the lengths of the other two sides,
• C is the angle between sides a and b.

In this case, we are given: CE = 4 DE = 5 C = 90º (a right angle)

We want to find CD.

Let's denote CD as 'c', CE as 'a', and DE as 'b'.

Using the Law of Cosines:

c^2 = a^2 + b^2 - 2ab * cos(C)

Substitute the given values:

c^2 = 4^2 + 5^2 - 2 * 4 * 5 * cos(90º)

Now, cos(90º) is 0, so the equation becomes:

c^2 = 16 + 25 - 0

c^2 = 41

Now, take the square root of both sides to find 'c':

c = √41 ≈ 6.4

Therefore, the value of CD is approximately 6.4 units.