Question

Синус острого угла A треугольника ABC равен 3√7/8. Найдите cosA

Answer 1

Решение задания приложено

Answer 2

To find the value of cos(A), we can use the Pythagorean identity, which states:

sin^2(A) + cos^2(A) = 1

Given that sin(A) = 3√7/8, we can square this value to find sin^2(A):

sin^2(A) = (3√7/8)^2 = 9*7/64 = 63/64

Now, we can solve for cos^2(A):

cos^2(A) = 1 - sin^2(A) = 1 - 63/64 = 1/64

Finally, we take the square root to find cos(A):

cos(A) = √(1/64) = 1/8

So, the value of cos(A) is 1/8.