Question

Вычислите площадь боковой поверхности конуса, если площадь его осевого сечения равно 12 см2, а площадь основы равно 16П см2. 30 Баллов. Решите, пожалуйста. Желательно, с дано и рисунком

Answer 1

Ответ: r=√16Π/Π=√16=4см; .... h=2*12/8=3см;... l=√r²+l²=√4²+3²=5; .... Sбок=Π*r*l=Π*4*5=20Πсм²

Чел, это задание 10-11 класса, а у тебя написано 5-9, манать ща всё торопят :)

Answer 2

Calculating the Lateral Surface Area of a Cone

To calculate the lateral surface area of a cone, we can use the formula:

Lateral Surface Area = π * r * l

Where: - r is the radius of the base of the cone - l is the slant height of the cone

Given: - The area of the base (A) = 16π cm² - The area of the axial section (B) = 12 cm²

We can use the relationship between the area of the base and the axial section to find the slant height (l) of the cone.

Finding the Slant Height (l)

The relationship between the area of the base and the axial section of a cone is given by the formula:

A = π * r^2 B = π * r * l

Where: - A is the area of the base - B is the area of the axial section - r is the radius of the base - l is the slant height

By rearranging the formula for the area of the axial section, we can solve for the slant height (l):

l = B / (π * r)

Substituting the given values: l = 12 / (π * r)

Calculating the Lateral Surface Area

Now that we have the slant height (l), we can calculate the lateral surface area using the formula:

Lateral Surface Area = π * r * l

Substitute the value of l: Lateral Surface Area = π * r * (12 / (π * r)) Lateral Surface Area = 12 cm²

This means that the lateral surface area of the cone is 12 cm².

Conclusion

The lateral surface area of the cone, given the area of its axial section and the area of its base, is 12 cm².