Question

ГЕОМЕТРИЯ!!! ДАЮ 50 БАЛЛОВ СРОЧНО Боковое ребро прямой призмы равно 4 см. Найдите объем призмы, если в ее основе лежит ромб с диагоналями 5 см и 12 см

Answer 1

Ответ:     V приз = 120 см³ .

Объяснение:

ABCDA₁B₁C₁D₁- пряма призма ;   ABCD - ромб ; d₁ = 5 cм  ; d₂ = 12 см ;

 АА₁ = Н = 4 см ;   V - ?

         V приз = S oc* H ;  V = 1/2 d₁ * d₂ * H = 1/2 *5 * 12 *4 = 120 ( см³ ) ;

        V приз = 120 см³ .

Answer 2

Calculating the Volume of a Prism with a Rhombus Base

To calculate the volume of a prism with a rhombus base, we can use the formula:

Volume = Area of Base × Height

First, we need to find the area of the rhombus base, and then we can use the given height to calculate the volume of the prism.

Finding the Area of the Rhombus Base

The area of a rhombus can be calculated using the formula:

Area = (d1 × d2) / 2

Where d1 and d2 are the diagonals of the rhombus.

Given: - d1 (first diagonal) = 5 cm - d2 (second diagonal) = 12 cm

Calculating the area: Area = (5 × 12) / 2 = 30 cm²

Calculating the Volume of the Prism

Given: - Base area = 30 cm² - Height = 4 cm

Using the formula: Volume = Base area × Height Volume = 30 cm² × 4 cm Volume = 120 cm³

So, the volume of the prism is 120 cubic centimeters.