Question

Помогите пожалуйста прошу вас дам 10 баллов Докажите что биссектриса соответственных углов при параллельных прямых параллельны ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

Ответ:

1.соответственные углы равны, значит

ит и биссектрисы их будут равны, но

если биссектрисы рассматривать

как прямые а секущую уже к ним, то

углы с секущей также будут равны

(соответственные) = параллельны.

2.240 = это скорее всего накрест

лежащие /2= 120… тупые все по 120,

острые по 60.

3. аксиома параллельности прямых - через

з точку не лежащей на прямой можно провести

вести только одну прямую, параллельную

заданной… значит 2 другие - пересекают

Объяснение:

вот ответы на все вопросы

Answer 2

Bisectors of Corresponding Angles in Parallel Lines

To prove that the bisectors of corresponding angles in parallel lines are parallel, we can use the following theorem:

Theorem: If two lines are parallel, then any transversal line that intersects them forms corresponding angles that are congruent.

Let's break down the proof step by step:

1. Given: Two parallel lines, line AB and line CD, and a transversal line EF that intersects them. 2. We want to prove: The bisectors of the corresponding angles formed by the transversal line EF are parallel.

Proof:

1. Let's assume that line EF intersects line AB at point G and line CD at point H. 2. Since line AB and line CD are parallel, we know that angle AGH and angle BGH are corresponding angles formed by the transversal line EF. 3. Let's assume that the bisector of angle AGH intersects line AB at point I and line CD at point J. 4. We need to prove that line IJ is parallel to line AB and line CD. 5. To prove this, we will use the theorem mentioned earlier: If two lines are parallel, then any transversal line that intersects them forms corresponding angles that are congruent. 6. Since line AB and line CD are parallel, angle AGH and angle BGH are congruent. 7. The bisector of angle AGH divides it into two congruent angles, angle AGI and angle IGH. 8. Similarly, the bisector of angle BGH divides it into two congruent angles, angle BGJ and angle JGH. 9. Since angle AGH and angle BGH are congruent, angle AGI and angle BGJ are also congruent. 10. By the transitive property of congruence, angle AGI and angle BGJ are congruent to angle IGH and angle JGH, respectively. 11. Therefore, angle IGH and angle JGH are congruent. 12. By the theorem mentioned earlier, since angle IGH and angle JGH are corresponding angles formed by the transversal line EF, line IJ must be parallel to line AB and line CD.

Thus, we have proved that the bisectors of corresponding angles formed by a transversal line in parallel lines are parallel.

Please let me know if you need any further clarification or assistance!