Question

В цилиндрический сосуд, в котором находится 4 литра воды, опущена деталь. При этом уровень жидкости в сосуде поднялся в 2,4 раза. Чему равен объем детали? Ответ выразите в литрах.

Answer 1

Ответ:
Vдет=5,6 л.

Решение:
V1=4*2,4=9,6 л. объем воды и детали вместе.
Vдет.=V1-Vводы=9,6-4=5,6 л. объем детали

Answer 2

Calculation of the Volume of the Object

To find the volume of the object that was submerged in the cylindrical vessel, we can use the principle of displacement. According to Archimedes' principle, the volume of the object is equal to the volume of liquid displaced by the object when it is submerged.

Given that the level of the liquid in the vessel rose by a factor of 2.4, we can conclude that the volume of the object is equal to 2.4 times the volume of the liquid displaced.

Since the initial volume of the liquid in the vessel was 4 liters, the volume of the liquid displaced is also 4 liters. Therefore, the volume of the object can be calculated as follows:

Volume of the object = 2.4 * Volume of the liquid displaced = 2.4 * 4 liters = 9.6 liters.

Thus, the volume of the object is 9.6 liters.

Please note that the provided information is based on the snippet from Source titled "Kvant Journal."