Question

В цилиндрический сосуд, в котором находится 6 дм3 воды, опущена деталь. При этом уровень жидкости в сосуде поднялся в 1,5 раза. Чему равен объём детали? Ответ выразите в кубических дециметрах.

Answer 1

6*1.5=9     9-6=3 dm3 ответ:3 dm3

Answer 2

Calculation of the Volume of the Object

To determine the volume of the object submerged in the cylindrical vessel, we can use the principle of displacement. According to Archimedes' principle, the volume of the object is equal to the volume of liquid displaced by the object when it is submerged.

Given that the level of the liquid in the vessel has risen by 1.5 times, we can calculate the volume of the object using the following formula:

Volume of the object = Volume of liquid displaced = Increase in volume of the liquid

Let's calculate the volume of the object using this formula.

The initial volume of the liquid in the vessel is 6 dm³. The level of the liquid has risen by 1.5 times, which means the increase in volume is 1.5 times the initial volume.

Increase in volume of the liquid = 1.5 * 6 dm³ = 9 dm³

Therefore, the volume of the object is 9 dm³.

Please note that the search results did not provide a direct answer to this specific question. However, the calculation is based on the principle of displacement, which is a fundamental concept in fluid mechanics.