
в прямоугольном треугольнике CDK с прямым углом D проведена высота DM. CM=12, MK=16. Найдите длины
сторон DK, CD, DM.

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Ответ:привет
Объяснение:привет



Given Information
We are given a right triangle CDK with a right angle at D. A height DM is drawn, and we are given that CM = 12 and MK = 16.Solution
To find the lengths of the sides DK, CD, and DM, we can use the properties of right triangles and the Pythagorean theorem.Let's start by finding the length of DK. Since DM is the height of the triangle, DK is the hypotenuse of the right triangle DCM. We can use the Pythagorean theorem to find DK.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (DK) is equal to the sum of the squares of the lengths of the other two sides (CD and CM).
Using this theorem, we have:
DK^2 = CD^2 + CM^2 (Equation 1)
Next, let's find the length of CD. We know that CM = 12, and since DM is the height of the triangle, CD is the base of the triangle. Therefore, CD = CM.
Finally, let's find the length of DM. We are given that MK = 16, and since DM is the height of the triangle, DM = MK.
Now, let's substitute the values we know into Equation 1 and solve for DK.
DK^2 = CD^2 + CM^2 (Equation 1)
DK^2 = CM^2 + CM^2 (Substituting CD = CM)
DK^2 = 2CM^2 (Simplifying)
DK = sqrt(2CM^2) (Taking the square root of both sides)
DK = sqrt(2) * CM (Simplifying)
Substituting the given value CM = 12, we can find DK:
DK = sqrt(2) * 12 (Substituting CM = 12)
DK = 12 * sqrt(2) (Simplifying)
Therefore, the length of DK is 12 * sqrt(2).
Since CD = CM = 12, the length of CD is 12.
And since


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