Question

AB=AC 5cm BC-6 см AD/ABC AD =12 ND-? AN-2​

Answer 1

Объяснение:

По моему должно быть правельно:)

Answer 2

Let's analyze the given information step by step.

1. AB = AC = 5cm: This implies that triangle ABC is an isosceles triangle, where AB and AC are congruent sides.

2. BC = 6cm: This is the length of the base of triangle ABC.

3. AD/ABC = 12: This implies that the length of line segment AD is 12 times the length of the entire triangle ABC.

Now, let's find the lengths of ND and AN.

Since AB = AC, triangle ABC is an isosceles triangle. Therefore, the altitude from vertex A to the base BC bisects BC.

Let's call the point where the altitude intersects BC as M. So, BM = MC = BC/2 = 6/2 = 3cm.

Since AD/ABC = 12, we can say that AD = 12 times the length of BC.

AD = 12 * BC = 12 * 6 = 72cm.

Since ND is the difference between AD and AM, and AM is half of BC, we have:

ND = AD - AM = 72 - 3 = 69cm.

Finally, AN can be found by subtracting ND from AD:

AN = AD - ND = 72 - 69 = 3cm.

Therefore, the lengths of ND and AN are 69cm and 3cm, respectively.