Question

В течении четверти Ваня получил следующие отметки по физике: одну "2", три"3", пять "4" и одна "5". Насколько среднее арифметическое его отметок отличается от медианы?

Answer 1

Calculation of the Mean and Median

To find the difference between the mean and median of Vanya's grades in physics, we first need to calculate both values.

Vanya received the following grades: one "2", three "3", five "4", and one "5".

To calculate the mean, we add up all the grades and divide by the total number of grades. In this case, the total number of grades is 10 (1 + 3 + 5 + 1).

The sum of the grades is: 2 + 3 + 3 + 3 + 4 + 4 + 4 + 4 + 4 + 5 = 36.

Therefore, the mean is: 36 / 10 = 3.6.

To calculate the median, we need to arrange the grades in ascending order: 2, 3, 3, 3, 4, 4, 4, 4, 4, 5.

The median is the middle value in the sorted list. Since there are 10 grades, the middle value is the average of the 5th and 6th grades, which are both 4.

Therefore, the median is 4.

Difference between the Mean and Median

Now that we have calculated the mean and median, we can find the difference between them.

The mean is 3.6, and the median is 4.

To find the difference, we subtract the median from the mean: 3.6 - 4 = -0.4.

Therefore, the difference between the mean and median of Vanya's grades in physics is -0.4.

Please note that the negative sign indicates that the mean is lower than the median.