Question

Разность двух натуральных чисел равна 43, а 54% одного числа равны 4/9 другого. Найдите эти числа. Желательно фото.

Answer 1

Problem Analysis

We are given that the difference between two natural numbers is 43, and that 54% of one number is equal to 4/9 of the other number. We need to find these two numbers.

Solution

Let's assume the two numbers are x and y, where x > y.

From the given information, we can write two equations:

1. x - y = 43 (Equation 1) 2. (54/100) * x = (4/9) * y (Equation 2)

To solve this system of equations, we can use substitution or elimination method. Let's use the substitution method.

From Equation 1, we can express x in terms of y: x = y + 43

Substituting this value of x in Equation 2, we get: (54/100) * (y + 43) = (4/9) * y

Simplifying this equation, we have: (27/50) * (y + 43) = (4/9) * y

Now, let's solve this equation to find the value of y.

Multiplying both sides of the equation by 450 (the least common multiple of 50 and 9) to eliminate the denominators, we get: 27 * 9 * (y + 43) = 50 * 4 * y

Simplifying further, we have: 243y + 11664 = 200y

Subtracting 200y from both sides, we get: 43y + 11664 = 0

Subtracting 11664 from both sides, we have: 43y = -11664

Dividing both sides by 43, we get: y = -11664 / 43

Calculating this value, we find: y ≈ -271.44

Since y is a natural number, it cannot be negative. Therefore, there is no solution to this problem.

Hence, there are no natural numbers that satisfy the given conditions.

Note: The solution is based on the given information and mathematical calculations. There is no need for a photo in this case.