Question

Сократите дробь(Теорема Виета)

Answer 1

1) х²+2х-35=0
D/4=36
х=-1+-6
х=-7; х=5⇒х²+2х-35=(х-5)(х+7)
2)2х²+13х-7=0
D=169+56=225
х=-7; х=0,5⇒2х²+13х-7=2(х+7)(х-0,5)=(х+7)(2х-1)
3)(х²+2х-35)/(2х²+13х-7)=(х-5)(х+7)/(х+7)(2х-1)=(х-5)/(2х-1)

Answer 2

$\frac{ {x}^{2} + 2x - 35 }{2x ^{2} + 13x - 7} = \frac{ {x}^{2} + 7x - 5x - 35 }{2 {x}^{2} + 14x - x - 7 } = \frac{x(x + 7) - 5(x + 7)}{2x(x + 7) -(x + 7) } = \frac{(x + 7)(x - 5)}{(x + 7)(2x - 1)} = \frac{x - 5}{2x - 1}$