Question

Решите неравенство

Answer 1

(2x^2+1)(2x^2-2)≤0

2x^2+1=0

x^2=-1/2

x∈(-∞, ∞)

 

2x^2-2=0

2x^2=2

x^2=1

(x-1)(x+1)≤0

x∈[-1, 1]