Question

Помогите с логарифмами пожалуйста

Answer 1

1. $log_3(3-x) = log_314-log_37 = log_3 \frac{14}{7} =log_32$
3-x = 2
x = 3-2
x = 1

2. $4log_9^2(6-x) - 4log_9(6-x) + 1 = 0; log_9(6-x)=t$
4t² -4t + 1 = (2t-1)²=0 => t=0.5
$log_9(6-x)=0.5$
$\sqrt{9} =6-x$
3=6-x
x=6-3
x=3

3. lg(x-3) - lg(7-x) = lg3
(x-3)/(7-x) = 3
x-3 = 21-3x
4x = 24
x = 6