Question

X^2+8x=-12 Помогите (((

Answer 1

$x^{2} -8x=-12$
$x^{2} -8x+12=0$
$D= (-8)^{2} - 4*1*12=64-48=16$
$x_{1}= \frac{8+ \sqrt{16} }{2} = \frac{12}{2} =6$
$x_{2}= \frac{8- \sqrt{16} }{2} = \frac{4}{2} =2$