Question

Два бидона вмещают 10,5 л. Если бы вместимость первого была в два раза больше, а вместимость второго на 8 л больше, чем в действительности, то общая емкость удвоилась бы. Какова емкость первого бидона?

Answer 1

X - емкость 1-го бидона
10,5 -x - емкость 2-го бидона
Общая емкость удвоилась, т. е. стала 10,5*2 =21 л
Можем составить уравнение
2x+(10,5-x)+8 = 21
решим его
2x -x = 21-18,5
x=2,5 л - емкость 1-го бидона

Answer 2

Problem Analysis

We are given that two containers together can hold 10.5 liters of liquid. If the capacity of the first container were twice as large and the capacity of the second container were 8 liters more than it actually is, then the total capacity would have doubled. We need to find the capacity of the first container.

Solution

Let's assume the capacity of the first container is x liters. According to the problem, the capacity of the second container is x + 8 liters.

If the capacity of the first container were twice as large, it would be 2x liters. And if the capacity of the second container were 8 liters more, it would be (x + 8 + 8) = (x + 16) liters.

According to the problem, if the capacities were as described, the total capacity would have doubled. So, the total capacity would be 2 * (x + (x + 16)) = 2 * (2x + 16) = 4x + 32 liters.

Since the actual total capacity is 10.5 liters, we can set up the equation:

4x + 32 = 10.5

Now, let's solve this equation to find the value of x.

4x = 10.5 - 32

4x = -21.5

x = -21.5 / 4

x = -5.375

The capacity of the first container is -5.375 liters.

Answer

The capacity of the first container is -5.375 liters.