Question

Из двух городов,расстояние между которыми 52 км,одновременно выехали навстречу друг другу два велосипедиста и встретились через два часа.Найдите скорость каждого велосипедиста,если известно,что второй велосипедист проежает за 3 ч на 18 больше,чем первый-за 2 ч.

Answer 1

Х- скорость первого,
у-скорость втрого
3у-2х=18у=(18+2х)/3 - скорость второго

2х+2*(18+2х)/3=522х+12-4х/3=52 10х/3=40х=40*3/10=12 км/ч - скорость 1-го

(18+2*12)/3=14 км/ч - скорость второго; 2*(14+12)=52 

Answer 2

Problem Analysis

We are given that two cyclists start simultaneously from two different cities and meet each other after two hours. The distance between the cities is 52 km. We need to find the speed of each cyclist given that the second cyclist travels for 3 hours and covers a distance 18 km more than the first cyclist, who travels for 2 hours.

Solution

Let's assume the speed of the first cyclist is x km/h. Since the first cyclist travels for 2 hours, the distance covered by the first cyclist is 2x km.

We are also given that the second cyclist travels for 3 hours and covers a distance 18 km more than the first cyclist. So, the distance covered by the second cyclist is 2x + 18 km.

Since the total distance between the cities is 52 km, we can write the equation:

2x + (2x + 18) = 52

Simplifying the equation, we get:

4x + 18 = 52

Subtracting 18 from both sides:

4x = 34

Dividing both sides by 4:

x = 8.5

So, the speed of the first cyclist is 8.5 km/h.

To find the speed of the second cyclist, we substitute the value of x into the equation:

2x + 18 = 2(8.5) + 18 = 17 + 18 = 35

Therefore, the speed of the second cyclist is 35 km/h.

Answer

The speed of the first cyclist is 8.5 km/h and the speed of the second cyclist is 35 km/h.