Question

Известно, что f(x)= cos2x Найти: 2f(x) , f(-x)+f(x) Помогите пожалуйста, очень срочно

Answer 1

2f(x)=2cos2x
f(-x)+f(x)=cos(-2x)+cos2x=cos2x+cos2x=2cos2x

Answer 2

Function f(x) = cos(2x)

The given function is f(x) = cos(2x). Let's calculate the values of 2f(x), f(-x), and f(x).

Calculating 2f(x)

To find 2f(x), we need to multiply f(x) by 2. Since f(x) = cos(2x), 2f(x) = 2 * cos(2x).

Calculating f(-x)

To find f(-x), we substitute -x into the function f(x) = cos(2x). So, f(-x) = cos(2(-x)) = cos(-2x).

Calculating f(x)

We already know that f(x) = cos(2x).

Now, let's calculate the values of 2f(x), f(-x), and f(x) using the given function.

1. 2f(x) = 2 * cos(2x) 2. f(-x) = cos(-2x) 3. f(x) = cos(2x)

Please note that without a specific value of x, we cannot provide the exact numerical values of 2f(x), f(-x), and f(x). However, we can discuss the general properties and behavior of the function.

If you have a specific value of x in mind, please provide it so that we can calculate the values accordingly.