Question

50 баллов срочна!!!!!!!!!!!

Answer 1

$(\sqrt{6})^x \leq \frac{1}{36}$

$(\sqrt{6})^x \leq 6^{-2}$

$(\sqrt{6})^x \leq (\sqrt{6})^{-4}$

$x \leq -4$

$x\in(-\infty;-4]$

$1.5^x\ \textless \ 2.25$

$1.5^x\ \textless \ 1.5^2$

$x\ \textless \ 2$

$x\in(-\infty;2)$