Question

1)1-(x-3)²=0 -Чему равен X 2)(x+2)^3=(4-x)^3 -Чему равен X 3)(x+1)^3+8=0 -Чему равен X 4)x²+6x+8=0 -Чему равен X Помогите пожалуйста очень надо!!!

Answer 1

2) (x+2)^3=(4-x)^3
3x+6=12-3x
3x+3x=12-6
6x=6
x=1

Answer 2

Решение уравнений:

1) 1 - (x - 3)² = 0

To solve this equation, we can expand the square and then isolate the variable x.

Expanding the square: 1 - (x - 3)² = 0 1 - (x² - 6x + 9) = 0 1 - x² + 6x - 9 = 0 - x² + 6x - 8 = 0

Now, we can solve this quadratic equation by factoring or using the quadratic formula. Let's use the quadratic formula:

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our case, a = -1, b = 6, and c = -8. Plugging these values into the quadratic formula, we get:

x = (-6 ± √(6² - 4(-1)(-8))) / (2(-1))

Simplifying further:

x = (-6 ± √(36 - 32)) / (-2) x = (-6 ± √4) / (-2) x = (-6 ± 2) / (-2)

This gives us two possible solutions:

x₁ = (-6 + 2) / (-2) = -4 / (-2) = 2 x₂ = (-6 - 2) / (-2) = -8 / (-2) = 4

Therefore, the solutions to the equation 1 - (x - 3)² = 0 are x = 2 and x = 4..

2) (x + 2)³ = (4 - x)³

To solve this equation, we can take the cube root of both sides and then isolate the variable x.

Taking the cube root of both sides: ∛((x + 2)³) = ∛((4 - x)³) x + 2 = 4 - x

Now, we can solve this equation for x:

x + 2 = 4 - x 2x = 2 x = 1

Therefore, the solution to the equation (x + 2)³ = (4 - x)³ is x = 1..

3) (x + 1)³ + 8 = 0

To solve this equation, we can isolate the variable x.

(x + 1)³ + 8 = 0 (x + 1)³ = -8

Now, we can take the cube root of both sides:

∛((x + 1)³) = ∛(-8) x + 1 = -2

Solving for x:

x + 1 = -2 x = -3

Therefore, the solution to the equation (x + 1)³ + 8 = 0 is x = -3..

4) x² + 6x + 8 = 0

To solve this equation, we can use the quadratic formula.

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our case, a = 1, b = 6, and c = 8. Plugging these values into the quadratic formula, we get:

x = (-6 ± √(6² - 4(1)(8))) / (2(1))

Simplifying further:

x = (-6 ± √(36 - 32)) / 2 x = (-6 ± √4) / 2 x = (-6 ± 2) / 2

This gives us two possible solutions:

x₁ = (-6 + 2) / 2 = -4 / 2 = -2 x₂ = (-6 - 2) / 2 = -8 / 2 = -4

Therefore, the solutions to the equation x² + 6x + 8 = 0 are x = -2 and x = -4..

I hope this helps! Let me know if you have any further questions.