Question

2 таких знака значит что это 1 большой { { 1. {x+2y=3 {2x+2y=4 2. {2x-y=1 {2x+y=3 3. {4z-5y=1 {5y-4z=3 4. {3a+4b=7 {5a+3b=8 5. {4x+3y=2 {5x+y=-3 6. {5n+4m=22 {3n-2m=0 Попроси больше объяснений Следить Отметить нарушение RusTakashi 01.03.2017 Войти чтобы добавить комментарий ОтветОтвет данEvgeshaBH 1.{x+2y=3 {2x+2y=4|*(-1) {x+2y=3 {-2x-2y=-4 методом алгебраического сложения_________-x=-1x=12.{2x-y=1 {2x+y=3________4x=4x=13.{4z-5y=1 {5y-4z=3{4z-5y=1{-4+5y=30=4Решений нет4.{3a+4b=7|*3{5a+3b=8|*(-4){9a+12b=21{-20a-12b=-32____________-11a=-11a=15.{4x+3y=2 {5x+y=-3|*(-3){4x+3y=2{-15x-3y=9________-11x=11x=-16.{5n+4m=22 {3n-2m=0|*2{5n+4m=22{6n-4m=0_________11n=22n=2 0.0 0 оценок 0 оценок Оцени! Оцени! Спасибо0 Комментарии Отметить нарушение Войти чтобы добавить комментарий Не тот ответ, который тебе нужен? Не тот ответ, который тебе нужен? Найди нужный Что ты хочешь узнать? Задай вопрос Премиум-доступсо Знаниями Плюс Начни учиться еще быстрее с неограниченным доступом к ответам от экспертов Подпишись Задай вопрос Самые новые вопросы VladDed Алгебра Нужно поздравление на 9 мая в стиле старорусского! Срочно пж даю 15 баллов​ ichkannnichtzahlen Алгебра 6*8^(-1/3) надо решение подобное, спасибо solomka2002 Алгебра [tex]\frac{1+ctg2x*ctgx}{tgx+ctgx}[/tex] С подробным объяснением пожалуйста

Answer 1

Solving Systems of Equations

To solve the given systems of equations, we can use various methods such as substitution, elimination, or matrix methods. Let's solve each system step by step.

1. {x + 2y = 3 {2x + 2y = 4

To solve this system, we can use the method of algebraic addition. By multiplying the second equation by -1 and adding it to the first equation, we can eliminate the y variable.

Multiplying the second equation by -1: {-2x - 2y = -4

Adding the equations: {-x = -1 x = 1

Substituting the value of x into the first equation: {1 + 2y = 3 {2y = 2 y = 1

Therefore, the solution to this system is x = 1 and y = 1.

2. {2x - y = 1 {2x + y = 3

To solve this system, we can use the method of algebraic addition. By adding the equations, we can eliminate the y variable.

Adding the equations: {4x = 4 x = 1

Substituting the value of x into the first equation: {2 - y = 1 {-y = -1 y = 1

Therefore, the solution to this system is x = 1 and y = 1.

3. {4z - 5y = 1 {5y - 4z = 3

To solve this system, we can use the method of algebraic addition. By adding the equations, we can eliminate the z variable.

Adding the equations: {-z = 4 z = -4

Substituting the value of z into the first equation: {4(-4) - 5y = 1 {-20 - 5y = 1 {-5y = 21 y = -4

Therefore, the solution to this system is z = -4 and y = -4.

4. {3a + 4b = 7 {5a + 3b = 8

To solve this system, we can use the method of algebraic addition. By multiplying the first equation by 3 and the second equation by -4, we can eliminate the b variable.

Multiplying the first equation by 3: {9a + 12b = 21

Multiplying the second equation by -4: {-20a - 12b = -32

Adding the equations: {-11a = -11 a = 1

Substituting the value of a into the first equation: {3(1) + 4b = 7 {3 + 4b = 7 {4b = 4 b = 1

Therefore, the solution to this system is a = 1 and b = 1.

5. {4x + 3y = 2 {5x + y = -3

To solve this system, we can use the method of algebraic addition. By multiplying the second equation by -3 and adding it to the first equation, we can eliminate the y variable.

Multiplying the second equation by -3: {-15x - 3y = 9

Adding the equations: {-11x = 11 x = -1

Substituting the value of x into the first equation: {4(-1) + 3y = 2 {-4 + 3y = 2 {3y = 6 y = 2

Therefore, the solution to this system is x = -1 and y = 2.

6. {5n + 4m = 22 {3n - 2m = 0

To solve this system, we can use the method of algebraic addition. By multiplying the second equation by 2 and adding it to the first equation, we can eliminate the m variable.

Multiplying the second equation by 2: {6n - 4m = 0

Adding the equations: {11n = 22 n = 2

Substituting the value of n into the first equation: {5(2) + 4m = 22 {10 + 4m = 22 {4m = 12 m = 3

Therefore, the solution to this system is n = 2 and m = 3.

I hope this helps! Let me know if you have any further questions.