Question

Найдите cos(a+b), cos2a, sin 2b, если sina =8/17, cos b=3/5

Answer 1

Cos(a+b)= cosa.cosb-sina.sinb,
cos2a = cos kv a- sin kv a
sin2b = 2.sinb . cosb.
Nado znat sinb a cos a.
sin kv b = 1- cos kv b = 1-9/25=16/25, sinb = 4/5
cos kv a = 1-sin kv a = 1-64/289 = 225/289, cos a = 15/17
cos(a+b)=15/17.3/5 - 8/17.4/5 =
cos 2a = 225/289 - 64/289 = 161/289
sin2b = 2. 4/5.3/5 = 24/25