Question

Дана функция у=f(x),нужно вычислить f(x)= система: х²,если -3 ≤ х ≤ 2 -х+2,если 2 < х ≤ 6. Вычислите: f(-3),f(2),f(3),f(6). Если что ≤ -это меньше или равно Желательно пишите с пояснениями.

Answer 1

На графике x=3, пустая незакрашенная точка т.к. знак строго меньше 3

Answer 2

Function Evaluation

The given function is defined as follows:

- For -3 ≤ x ≤ 2: f(x) = x². - For 2 < x ≤ 6: f(x) = -x + 2.

Let's evaluate the function for the given values:

1. f(-3): - Since -3 is within the range of -3 ≤ x ≤ 2, we use the first part of the function: f(x) = x². - Substituting x = -3, we get f(-3) = (-3)² = 9.

2. f(2): - Since 2 is within the range of 2 < x ≤ 6, we use the second part of the function: f(x) = -x + 2. - Substituting x = 2, we get f(2) = -(2) + 2 = 0.

3. f(3): - Since 3 is within the range of 2 < x ≤ 6, we use the second part of the function: f(x) = -x + 2. - Substituting x = 3, we get f(3) = -(3) + 2 = -1.

4. f(6): - Since 6 is within the range of 2 < x ≤ 6, we use the second part of the function: f(x) = -x + 2. - Substituting x = 6, we get f(6) = -(6) + 2 = -4.

Therefore, the values of the function for the given inputs are: - f(-3) = 9 - f(2) = 0 - f(3) = -1 - f(6) = -4