Question

В двух сараях сложено сено, причём в первом сарае сена в 3 раза больше, чем во втором. После того, как из первого сарая переложили во второй 20 тонн сена и ещё привезли во второй сарай 10 тонн, то в обоих сараях сена стало поровну. Сколько тонн сена было в каждом сарае первоначально?

Answer 1

Пусть во втором сарае было х тонн сена, а в первом 3х тонн сена, тогда

3х-20=х+20+10

3х-х=20+10+20

2х=50

х=25 тонн -было изначально во втором сарае

тогда в первом сарае было 25*3=75 тонн

Ответ: в первом сарае было 75 тонн сена, а во втором было 25 тонн:)

 

 

 

 

 

 

 

 

 

 

 

 

 

Answer 2

Problem Analysis

We are given two barns, with the first barn having three times as much hay as the second barn. After transferring 20 tons of hay from the first barn to the second barn and then adding 10 tons more to the second barn, the hay is evenly distributed between the two barns. We need to determine the initial amount of hay in each barn.

Solution

Let's assume the initial amount of hay in the second barn is x tons. According to the problem, the first barn has three times as much hay as the second barn, so the initial amount of hay in the first barn is 3x tons.

After transferring 20 tons of hay from the first barn to the second barn, the first barn will have 3x - 20 tons of hay, and the second barn will have x + 20 tons of hay.

Then, an additional 10 tons of hay is added to the second barn, resulting in both barns having an equal amount of hay. Therefore, we can set up the equation:

3x - 20 = x + 20 + 10

Simplifying the equation:

3x - x = 20 + 10 + 20

2x = 50

x = 25

So, the initial amount of hay in the second barn was 25 tons, and the initial amount of hay in the first barn was 3 * 25 = 75 tons.

Answer

The initial amount of hay in each barn was 75 tons in the first barn and 25 tons in the second barn.