Question

В одном пенале y карандашей а в другом - в 4 раза больше. в первый пенал добавили 5 карандашей,а из второго вынули 7 карандашей. карандашей в пеналах стало поровну.выясните,сколько карандашей было в первом пенале

Answer 1

Первым дейстивем у карандашей умножаем на 4 потом получим скоко в во втором пенале корондошей потом у прибовлЕм к 5 а из второго пенала минусуем7 карандашей и все

Answer 2

Problem Analysis

We are given two pencil cases, where one has y number of pencils and the other has 4 times as many pencils. We are also told that 5 pencils were added to the first pencil case, and 7 pencils were removed from the second pencil case. After these operations, the number of pencils in both cases became equal. We need to determine the initial number of pencils in the first pencil case.

Solution

Let's assume the initial number of pencils in the first pencil case is x. According to the problem, the second pencil case initially had 4 times as many pencils, which means it had 4x pencils.

After adding 5 pencils to the first pencil case, it will have x + 5 pencils. And after removing 7 pencils from the second pencil case, it will have 4x - 7 pencils.

Since the number of pencils in both cases became equal, we can set up the following equation:

x + 5 = 4x - 7

Now, let's solve this equation to find the value of x.

x - 4x = -7 - 5 -3x = -12 x = -12 / -3 x = 4

Therefore, the initial number of pencils in the first pencil case was 4.

Answer

The initial number of pencils in the first pencil case was 4.