Question

Сократить дробь 7(x^2+2xy+y^2)/3x+3y помогите пожалуйста

Answer 1

$\frac{7(x^2+2xy+y^2)}{3x+3y}= \frac{7(x+y)^2}{3(x+y)}= \frac{7}{3}(x+y)$

Answer 2

Solving the Fraction

To simplify the given fraction 7(x^2+2xy+y^2)/3x+3y, we can factor the numerator and denominator and then cancel out any common factors.

The numerator can be factored as 7(x+y)^2 and the denominator can be factored as 3(x+y).

So, the fraction simplifies to 7(x+y)^2 / 3(x+y).

Therefore, the simplified form of the given fraction is 7(x+y) / 3.

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