Question

Решите систему уравнений 12x+3y-9=2x+10 8x+20=10+2(3x+2y)Зарание спасибо всем помогавшим)

Answer 1

12x+3y-9=2x+10,            12х-2х+3у=10+9,    10х+3у=19,
8x+20=10+2(3x+2y);        8х-6х-4у=10-20;      2х-4у=-10;  изените но продолжения не знаю(

Answer 2

Solving the System of Equations

To solve the system of equations 12x + 3y - 9 = 2x + 10 and 8x + 20 = 10 + 2(3x + 2y), we can use the method of substitution or elimination to find the values of x and y that satisfy both equations.

Using the Method of Substitution

We can start by solving the first equation for y in terms of x: 12x + 3y - 9 = 2x + 10 3y = 2x + 10 - 12x + 9 3y = -10x + 19 y = (-10/3)x + 19/3

Now, we can substitute the expression for y into the second equation: 8x + 20 = 10 + 2(3x + 2((-10/3)x + 19/3)) 8x + 20 = 10 + 6x + 4(-10/3)x + 4(19/3) 8x + 20 = 10 + 6x - 40/3x + 76/3 8x - 6x + 40/3x = 10 - 20/3 22/3x = 10 - 20/3 22/3x = 30/3 - 20/3 22/3x = 10/3 x = 10/22 x = 5/11

Now that we have found the value of x, we can substitute it back into the expression for y: y = (-10/3)(5/11) + 19/3 y = -50/33 + 19/3 y = -50/33 + 209/99 y = -550/363 + 209/99 y = (-550*3 + 209*11)/(363*3) y = (-1650 + 2299)/1089 y = 649/1089 y = 649/1089

Conclusion

Therefore, the solution to the system of equations is x = 5/11 and y = 649/1089.