Question

Из пунктов А и В ,расстояние между которыми 1020 км,отправились одновременно навстречу друг другу два поезда,причем скорость одного на 10 км/ч больше скорости другого.Через 5 ч поезда,ещё не встретившись,находились на расстоянии 170 км друг от друга.Найдите скорости поездов.

Answer 1

Пусть скорость первого поезда V, тогда второго V-10, из условия задачи можно составить следующее уравнение
1020-5(V+V-10)=170
10V-50=850 ⇒ V=90 км\ч - скорость первого поезда
V-10=90-10=80 км\ч - скорость второго поезда

Answer 2

Problem Analysis

We have two trains, A and B, traveling towards each other from points A and B, respectively. The distance between the two points is 1020 km. The trains started at the same time, and the speed of one train is 10 km/h greater than the speed of the other train. After 5 hours, the trains were still 170 km apart. We need to find the speeds of the trains.

Solution

Let's assume the speed of train A is x km/h, and the speed of train B is (x + 10) km/h.

We can use the formula: distance = speed × time.

After 5 hours, the distance traveled by train A is 5x km, and the distance traveled by train B is 5(x + 10) km.

According to the problem, the sum of the distances traveled by the two trains is 1020 km, and they are 170 km apart. So we can write the equation:

5x + 5(x + 10) + 170 = 1020

Simplifying the equation:

5x + 5x + 50 + 170 = 1020 10x + 220 = 1020 10x = 800 x = 80

Therefore, the speed of train A is 80 km/h, and the speed of train B is 90 km/h.

Answer

The speed of train A is 80 km/h, and the speed of train B is 90 km/h.