
B^3-25b=0помогите срочно


Ответы на вопрос

b*(b²-25)=0
b=0 b²-25=0 ⇒ b=5 , b=-5



Solving the Equation B^3 - 25b = 0
To solve the equation B^3 - 25b = 0, we need to find the values of B that satisfy the equation.
One way to solve this equation is by factoring out the common factor, which in this case is b. By factoring out b, we get:
b(B^2 - 25) = 0
Now, we have two factors: b = 0 and B^2 - 25 = 0. Let's solve each factor separately.
Factor 1: b = 0
When b = 0, the equation becomes 0(B^2 - 25) = 0. This means that any value of B will satisfy the equation when b = 0.
Factor 2: B^2 - 25 = 0
To solve this quadratic equation, we can factor it as the difference of squares:
(B - 5)(B + 5) = 0
Setting each factor equal to zero, we have two possibilities:
B - 5 = 0 --> B = 5
B + 5 = 0 --> B = -5
Therefore, the solutions to the equation B^3 - 25b = 0 are B = 5, B = -5, and any value of B when b = 0.
Please note that these solutions are derived from the equation B^3 - 25b = 0 and the factoring method. If you have any further questions or need additional assistance, feel free to ask!


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